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-rw-r--r--src/modules/m_spanningtree.cpp91
1 files changed, 67 insertions, 24 deletions
diff --git a/src/modules/m_spanningtree.cpp b/src/modules/m_spanningtree.cpp
index e94209885..de2bc3923 100644
--- a/src/modules/m_spanningtree.cpp
+++ b/src/modules/m_spanningtree.cpp
@@ -1515,57 +1515,96 @@ class TreeSocket : public InspSocket
/** FJOIN, similar to unreal SJOIN */
bool ForceJoin(std::string source, std::deque<std::string> &params)
{
+ /* 1.1 FJOIN works as follows:
+ *
+ * Each FJOIN is sent along with a timestamp, and the side with the lowest
+ * timestamp 'wins'. From this point on we will refer to this side as the
+ * winner. The side with the higher timestamp loses, from this point on we
+ * will call this side the loser or losing side. This should be familiar to
+ * anyone who's dealt with dreamforge or TS6 before.
+ *
+ * When two sides of a split heal and this occurs, the following things
+ * will happen:
+ *
+ * If the timestamps are exactly equal, both sides merge their privilages
+ * and users, as in InspIRCd 1.0 and ircd2.8. The channels have not been
+ * re-created during a split, this is safe to do.
+ *
+ *
+ * If the timestamps are NOT equal, the losing side removes all privilage
+ * modes from all of its users that currently exist in the channel, before
+ * introducing new users into the channel which are listed in the FJOIN
+ * command's parameters. This means, all modes +ohv, and privilages added
+ * by modules, such as +qa. The losing side then LOWERS its timestamp value
+ * of the channel to match that of the winning side, and the modes of the
+ * users of the winning side are merged in with the losing side. The loser
+ * then sends out a set of FMODE commands which 'confirm' that it just
+ * removed all privilage modes from its existing users, which allows for
+ * services packages to still work correctly without needing to know the
+ * timestamping rules which InspIRCd follows. In TS6 servers this is always
+ * a problem, and services packages must contain code which explicitly
+ * behaves as TS6 does, removing ops from the losing side of a split where
+ * neccessary within its internal records, as this state information is
+ * not explicitly echoed out in that protocol.
+ *
+ * The winning side on the other hand will ignore all user modes from the
+ * losing side, so only its modes get applied. Life is simple for those
+ * who succeed at internets. :-)
+ */
+
if (params.size() < 3)
return true;
- char first[MAXBUF];
- char modestring[MAXBUF];
- char* mode_users[127];
- memset(&mode_users,0,sizeof(mode_users));
- mode_users[0] = first;
- mode_users[1] = modestring;
- strcpy(modestring,"+");
- unsigned int modectr = 2;
+ char first[MAXBUF]; /* The first parameter of the mode command */
+ char modestring[MAXBUF]; /* The mode sequence (2nd parameter) of the mode command */
+ char* mode_users[127]; /* The values used by the mode command */
+ memset(&mode_users,0,sizeof(mode_users)); /* Initialize mode parameters */
+ mode_users[0] = first; /* Set this up to be our on-stack value */
+ mode_users[1] = modestring; /* Same here as above */
+ strcpy(modestring,"+"); /* Initialize the mode sequence to just '+' */
+ unsigned int modectr = 2; /* Pointer to the third mode parameter (e.g. the one after the +-sequence) */
- userrec* who = NULL;
- std::string channel = params[0];
- time_t TS = atoi(params[1].c_str());
- char* key = "";
+ userrec* who = NULL; /* User we are currently checking */
+ std::string channel = params[0]; /* Channel name, as a string */
+ time_t TS = atoi(params[1].c_str()); /* Timestamp given to us for remote side */
+ /* Try and find the channel */
chanrec* chan = this->Instance->FindChan(channel);
- if (chan)
- key = chan->key;
+ /* Initialize channel name in the mode parameters */
strlcpy(mode_users[0],channel.c_str(),MAXBUF);
- /* default is a high value, which if we dont have this
+ /* default TS is a high value, which if we dont have this
* channel will let the other side apply their modes.
*/
time_t ourTS = time(NULL)+600;
+ /* Does this channel exist? if it does, get its REAL timestamp */
if (chan)
ourTS = chan->age;
- /* XXX: PAY ATTENTION:
- * In 1.1, if they have the newer channel, we immediately clear
+ /* In 1.1, if they have the newer channel, we immediately clear
* all status modes from our users. We then accept their modes.
* If WE have the newer channel its the other side's job to do this.
* Note that this causes the losing server to send out confirming
* FMODE lines.
*/
if (ourTS > TS)
-// || (this->Instance->ULine(source.c_str())))
{
- Instance->Log(DEBUG,"FJOIN detected, our TS=%lu, their TS=%lu",ourTS,TS);
std::deque<std::string> param_list;
+
if (chan)
chan->age = TS;
+
+ /* XXX: Lower the TS here */
ourTS = TS;
+
param_list.push_back(channel);
- Instance->Log(DEBUG,"REMOVE ALL STATUS MODES FROM OUR USERS *NOW*");
+ /* Zap all the privilage modes on our side */
this->RemoveStatus(Instance->Config->ServerName, param_list);
}
+ /* Put the final parameter of the FJOIN into a tokenstream ready to split it */
irc::tokenstream users(params[2]);
std::string item = "*";
@@ -1574,16 +1613,20 @@ class TreeSocket : public InspSocket
*/
params[2] = ":" + params[2];
DoOneToAllButSender(source,"FJOIN",params,source);
+
+ /* Now, process every 'prefixes,nick' pair */
while (item != "")
{
+ /* Find next user */
item = users.GetToken();
- /* process one user at a time, applying modes. */
- char* usr = (char*)item.c_str();
+
+ const char* usr = item.c_str();
+
/* Safety check just to make sure someones not sent us an FJOIN full of spaces
* (is this even possible?) */
if (usr && *usr)
{
- char* permissions = usr;
+ const char* permissions = usr;
int ntimes = 0;
char* nm = new char[MAXBUF];
char* tnm = nm;
@@ -1625,7 +1668,7 @@ class TreeSocket : public InspSocket
Instance->Log(DEBUG,"Fake direction in FJOIN, user '%s'",who->nick);
continue;
}
- chanrec::JoinUser(this->Instance, who, channel.c_str(), true, key);
+ chanrec::JoinUser(this->Instance, who, channel.c_str(), true, "");
if (modectr >= (MAXMODES-1))
{
/* theres a mode for this user. push them onto the mode queue, and flush it